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OpenStudy (gorv):
first convert the line in standard form
OpenStudy (gorv):
y=mx+c
OpenStudy (gorv):
yeah now make y coefficient= 1
OpenStudy (gorv):
gud
y=-2x/3 +-5/3
OpenStudy (gorv):
what is slope of line ??
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OpenStudy (gorv):
in standard form slope=m
OpenStudy (gorv):
okay
OpenStudy (gorv):
perpendicular line have property that product of their slope = -1
OpenStudy (gorv):
let slope of perpendicular line =m1
so (-2/3)*m1=-1
OpenStudy (gorv):
tel me m1=???
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OpenStudy (texaschic101):
if you want a perpendicular line, you need the negative reciprocal. To find the negative reciprocal, just " flip " the slope and change the sign
OpenStudy (gorv):
2x-3y-5=0
2x-5=3y
y=2x/3-5/3
OpenStudy (gorv):
your ans is correct
OpenStudy (texaschic101):
wait...pixiedust....the slope is 2/3....to find perpendicular line. flip the slope and change the sign...so 2/3 would become -3/2
OpenStudy (gorv):
yeah that's what she answered
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OpenStudy (gorv):
@PixieDust1 you ans correctly
OpenStudy (texaschic101):
2x - 3y - 5 = 0
-3y = -2x + 5
y = 2/3x - 5/3
she answered correctly, but she got the slope wrong...it is not a negative slope, it is 2/3. Then you flip it and change the sign making the slope we need -3/2