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Mathematics 8 Online
OpenStudy (pixiedust1):

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OpenStudy (gorv):

first convert the line in standard form

OpenStudy (gorv):

y=mx+c

OpenStudy (gorv):

yeah now make y coefficient= 1

OpenStudy (gorv):

gud y=-2x/3 +-5/3

OpenStudy (gorv):

what is slope of line ??

OpenStudy (gorv):

in standard form slope=m

OpenStudy (gorv):

okay

OpenStudy (gorv):

perpendicular line have property that product of their slope = -1

OpenStudy (gorv):

let slope of perpendicular line =m1 so (-2/3)*m1=-1

OpenStudy (gorv):

tel me m1=???

OpenStudy (texaschic101):

if you want a perpendicular line, you need the negative reciprocal. To find the negative reciprocal, just " flip " the slope and change the sign

OpenStudy (gorv):

2x-3y-5=0 2x-5=3y y=2x/3-5/3

OpenStudy (gorv):

your ans is correct

OpenStudy (texaschic101):

wait...pixiedust....the slope is 2/3....to find perpendicular line. flip the slope and change the sign...so 2/3 would become -3/2

OpenStudy (gorv):

yeah that's what she answered

OpenStudy (gorv):

@PixieDust1 you ans correctly

OpenStudy (texaschic101):

2x - 3y - 5 = 0 -3y = -2x + 5 y = 2/3x - 5/3 she answered correctly, but she got the slope wrong...it is not a negative slope, it is 2/3. Then you flip it and change the sign making the slope we need -3/2

OpenStudy (texaschic101):

anytime :)

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