write an equation of a line in slope-intercept form for that is parallel to y=5x-10 and passes through the point (9,-3)

Question

shinalcantara · Answer

since the line is parallel to the equation y=5x-10, then
the line's slope is the same as that of the line of the equation.
REMEMBER that y-intercept form is the defined by the formula
y=mx + b where m is the slope and b being the y-intercept.
Based on the given equation, what would be the slope of the line?

anonymous · Answer

the answer is y=5x-48 can you please explain how that is the answer @shinalcantara

shinalcantara · Answer

since the slope of the line is 5 and you have a point (9,-3),
all you have to remember when dealing with equation of the line with given slope and a point is the slope formula
$$m = \frac{ y2-y1 }{ x2-x1 }$$
substitute the values
$$ 5 = \frac{ y - (-3) }{ x-9 }$$
cross multiply (x-9)
$$5(x-9)=y+3$$
$$5x - 45 = y + 3$$
rearranging
$$y = 5x - 45 - 3$$
$$y = 5x - 48$$