Math test tomorrow and am trying to understand how to do slope which I am so bad in, how do i solve parallel to 2x-2y=8 through (-1,2) and Perpendicular to -2x+4y=6 through (3,4)
Put them in slope-intercept form first and then we will go from there
2y=2x+b
Now divide both sides by 2
y=x+8
Now do the second one
idk im just gonna skip it for now
Cause there is a trick to it and i forgot how to do it
Do you want me to just give you the answer and the trick for perpendicular lines?
Yes please
One moment. Let me make it to where I can show you how I did it and allow you to refer to it in the future
Here is parallel
Isnt -2y supposed to be positive since youre adding it to the other side
and -2x isnt supposed to be -
In which one?
The parallel one where its being turned into standard form
Yes it it because in order to move it to the other side you have to do the opposite of its sign. In this case its a positive 2x, so you would subtract 2x, resulting in it becoming -2x
How? you have to add 2y since its already a - and make it equal 2x , i thought you only move the y not the x
No, you move the x because you're trying to get it into slope-intercept. Which is y=mx+b
Here is perpendicular though
But it could be either way anyway
No it cannot. You're trying to find two equations in slope-intercept that are parallel and perpendicular.
Okey then, thank you very much for your help
Do you understand it? But you're welcome
I better or if not ill flunk my math exam tomorrow...
Study with the screenshots I gave you. Take different problems and try to apply them. If you need help, I'm here.
thank you :)
You're welcome :)
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