Find the first three terms of the geometric sequence where the first term is 4 and the common ratio is 1/2 HELP MEDALS GIVEN
Multiply first term by common ratio to get the second term. Multiply second term by common ratio to get the third term.
HOW PLEASE can you shoiw me
First term is 4 Second term = First term * common ratio = 4 * 1/2 = ?
2 right
Yes. First term is 4 Second term = First term * common ratio = 4 * 1/2 = 2 Third term = Second term * 1/2 = 2 * 1/2 = 1 So the first three terms of the geometric sequence are: 4, 2, 1
i have to pass this test i ahve the answer choices
Is 4, 2, 1 among the choices?
omgggg thank can you help with some more pleaseee
I am not supposed to be helping with tests. Sorry.
this is the study guide i have to know the material to pass the test this isnt the actually test thats why im asking for help
I can assist you but you have to do the work yourself. I will try one more.
Find the first three terms of the sequence: dn=3/5n-1
Is it \[ d_n = \frac{3}{5n-1}\] ?
yesss can you please whow me how you typed that???
You can click on the Equation button below the reply box and choose what you want from the right hand side.
do you know how to put it in wolfram alpha ?
It is so simple to do it than to come up with instructions for wolfram to do it.
Just put n = 1 on the right hand side and evaluate. That will be the first term. Put n = 2 on the right hand side and evaluate. That will be the second term.
okay lollll im a little slow with things
3 / (5n - 1) n = 1 3 / (5 - 1) = 3/4 is the first term. put n = 2 in 3 / (5n - 1) and evaluate to get the second term. put n = 3 in 3 / (5n - 1) and evaluate to get the third term.
okay so the answer is
nevermid i got ittttt
hey how do you put this in a calculator on wolfram
a6= 4n^2+5/7n^3+n
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