Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h. Car A traveled 22 mph faster than Car B. How fast did Car A travel?
@IMStuck
Set up a table so it's easy to see what you have:
|dw:1412121063268:dw|
Now let's fill it in. The distances are the same, so let's put a d in each of those.
|dw:1412121119650:dw|
k
Now we have the times for cars. A is 2.4 and B is 4, so let's fill those in.
|dw:1412121156204:dw|
Now it tells us that car B is travelling at a rate 22 miles faster than car A. So that looks like this:
|dw:1412121205720:dw|
The distances traveled are the same, so we can set the rate and time of one car equal to the rate and time of the other car. The distance formula is distance = rate times time, so the rate and the time are multiplied together and set equal to one another. Like this:
|dw:1412121281999:dw|
So thats the equation. 2.4r = 4(22+r) Can you solve that for r?
ya
WAIT!!!!!
I mixed up the rates. Let me redo them. Sorry!
|dw:1412121445269:dw|
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