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Mathematics
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Differentiate the Function
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\[y=\frac{ 4x ^{2}+8x+6 }{ \sqrt{x} }\]
well that's an easy one quotient rule do you know it?
\((\frac{u}{v})'=\frac{u'v-uv'}{v^2}\)
\(u=4x^2+8x+6\) \(v=sqrt{x}\)
let me ask you what is the derivative of \(4x^2+8x+6\) and also what is the derivative of \(\sqrt{x}\)
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you could use law of exponents before differentiating
\[y=4x^{2-\frac{1}{2}}+8x^{1-\frac{1}{2}}+6x^{0-\frac{1}{2}}\] hope you can differentiate that :)
power rule is needed
eh yeah that's another way of looking at it @freckles and actually i prefer dealing with power rule much better than quotient rule
isn't x=1
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dx/dx is 1 but x isn't 1
then what would it be?
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