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Mathematics 13 Online
OpenStudy (anonymous):

Differentiate the Function

OpenStudy (anonymous):

\[y=\frac{ 4x ^{2}+8x+6 }{ \sqrt{x} }\]

OpenStudy (xapproachesinfinity):

well that's an easy one quotient rule do you know it?

OpenStudy (xapproachesinfinity):

\((\frac{u}{v})'=\frac{u'v-uv'}{v^2}\)

OpenStudy (xapproachesinfinity):

\(u=4x^2+8x+6\) \(v=sqrt{x}\)

OpenStudy (xapproachesinfinity):

let me ask you what is the derivative of \(4x^2+8x+6\) and also what is the derivative of \(\sqrt{x}\)

OpenStudy (freckles):

you could use law of exponents before differentiating

OpenStudy (freckles):

\[y=4x^{2-\frac{1}{2}}+8x^{1-\frac{1}{2}}+6x^{0-\frac{1}{2}}\] hope you can differentiate that :)

OpenStudy (freckles):

power rule is needed

OpenStudy (xapproachesinfinity):

eh yeah that's another way of looking at it @freckles and actually i prefer dealing with power rule much better than quotient rule

OpenStudy (anonymous):

isn't x=1

OpenStudy (freckles):

dx/dx is 1 but x isn't 1

OpenStudy (anonymous):

then what would it be?

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