Question

I need some help with my Algebra 2 work please.

Answer 1

post a problem you need help with ...

Answer 2

suppose a and b vary inversley andb=8 when a=6. write a function that models the variation and find b when a =30

Answer 3

ok, so how does your material define an inverse relationship?

Answer 4

I know of inverse variation as when x increase y increase

Answer 5

hmm, thats a direct variation

inverse is when one gets big, the other gets small

Answer 6

Oh whoops I always get them messed up

Answer 7

i get them messed up only half the time :)

so, let ab = k for all a,b

Answer 8

we know that 8(6) = k for all a,b

therefore: 30b = 48, what is b?

Answer 9

b=1.6

Answer 10

8/5 is what im getting

Answer 11

1.6, yeah :)

Answer 12

I just kinda divided 48 and 30

Answer 13

me too

Answer 14

is that all i have to do?

Answer 15

well, the key is in knowing how the relationship works

if a and b are inversly related, then they have the form: ab=k for some constant k

or a = k/b

Answer 16

finding k and equating it to the new values is all there is to it yes

Answer 17

Oh okay

Answer 18

can you help me with another one @amistre64

Answer 19

i can try one more ...

Answer 20

what is the quotient in simplest form? state any restrictions on the variable
z^2-4/z-3 divide z+2/z^2+z-12

Answer 21

you are going to have to factor the parts to see if anything is common top to bottom

Answer 22

restrictions are what makes a bad math happen, in this case its most likely what makes us divide by zero

Answer 23

im going to want to see youre attempt, or ask questions if something is a bit odd to you