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OpenStudy (anonymous):
is the answer; a/30 - 1 ?
OpenStudy (anonymous):
A^-1 (f) = 30 (f - 1)
OpenStudy (anonymous):
im so confused :(
OpenStudy (anonymous):
Write it as A(f) = (30 + f)/30
and then go from there.
OpenStudy (anonymous):
Did you understand it yet ?
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OpenStudy (anonymous):
Or you want me to elaborate it ?
OpenStudy (anonymous):
elaborate please
OpenStudy (anonymous):
ok give me a sec.
OpenStudy (anonymous):
Replace A(f) with "y"
so it will be
y = 1 + f/30
Now switch "y" with "f"
f = 1 + y/30
multiply by 30 on both sides
30f = 30 + y
Now
30f -30 = 30 +y -30
which leaves us
30f -30 = y
Now
y = 30 (f - 1)
Replace "y" with
A^-1(f)
OpenStudy (anonymous):
ok I believe I got it ... thanks
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OpenStudy (anonymous):
Welcome.
OpenStudy (anonymous):
wait sorry ....I don't understand the - 30 in front of y
OpenStudy (anonymous):
-30 on both sides to remove the +30 with "y", Because you can not just do -30 on one side. The equation has to be balanced.
OpenStudy (anonymous):
Or you can just do this
30f = 30 + y
30f - 30 = y
and then continue.