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6. Name the like terms in the following expression. 5m + 4 + 3m + 6p 7. Write an equation for the following: Twelve times h equals one hundred twenty minus thirty-six.State whether the equation is true, false, or an open sentence. Explain. 8. Use the Distributive Property to simplify. Show all steps. 8(6 – 2) (2 points) 9. Use the Distributive Property to multiply. Show all steps. 7(c + 4) (2 points) 10. Simplify the following expression. z – 2z + 4z + 6
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@B.R I am sorry I am not used to help in Mathematics.
Okaaayyy....
This is what you need to know for problem 6. Polynomials are made of terms. A term has to have a number and zero or more variables (letters). If two terms have exactly the same variables and with the same exponents, then the terms are like terms.
For problem 7, do this: "Twelve times h" is 12h "one hundred twenty minus thirty-six" is 120 - 36 Since the sentence includes the word equals, use the equal sign: = The equation is 12h = 120 - 36 That can be simplified to 12h = 84 by combining like terms on the right side. Now the question is whether this equation is true, false, or open. That depends on the value of h. There is a certain value of h that will make the equation true. Since all we have is 12h = 84, we cannot call it either true or false. That means it's an open sentence.
Problem 8. The distributive property is this: a(b - c) = ab - ac Here is an example with numbers: 6(8 - 2) = 6 * 8 - 6 * 2 = 48 - 12 = 36 Do exactly the same as I did in the example using the numbers of your problem.
Problem 9 uses the distributive property with a sum. Here is the distributive property: a(b + c) = ab + ac Here is an example similar to yours: 5(b + 3) = 5b + 5 * 3 = 5b + 15 Now try your example using what I did above.
10. When a variable is written alone, it means 1 times the variable. Examples z = 1z x = 1x b = 1b When you combine like terms (terms with the same variable part), just add the numbers of the terms (called coefficients) and then write the variable part. Examples: 4x + 5x = 9x 6x - 3x = 3x z + 2z = 3z (because z is really 1z, so 1z + 2z = 3z) 6x - 2x + 6x = 10x In problem 10, there are three li9ke terms with the variable z that can be combined together. The number has to be left as a number added to the rest.
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