Question

find the inverse of: (will write the equation below)

Answer 1

\[g(x)=\sqrt[3]{7-3x}\]

Answer 2

lets say g(x) = y. Now switch x and y and solve for y...

cube both sides = x^3 = 7-3y

minus 7 = x^3 - 7 = -3y

divide by -3...

y = (x^3 - 7)/-3

Answer 3

\[y = \frac{ -(x^3 - 7) }{ 3 }\]

Answer 4

Ok, thank you. I have trouble with doing the anything square rooted on inverses. How would I work out \[\frac{ 3 }{ \sqrt{3x+5} }\] ? You don't have to give me the answer, just the layout on how to work it out

Answer 5

so replace x and y and tell me what that is

Answer 6

ok now multiply both sides by the denominator