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Write the general form of the equation of each circle. Center at the point (4,6) and tangent to the x-axis.
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ok then i go to bed
Lol. Okay. :]
ok that was wrong \[(x-4)^2+(y-6)^2=r^2\]
now where do you think you will find \(r\) ?
i.e. how far is \((4,6)\) from the \(x\) axis? (don't think too hard)
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want a hint?
6 away?
Yes please!
you don't need one clearly
|dw:1412222825988:dw|
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so yeah it is 6 units away final answer \[(x-4)^2+(y-6)^2=36\]
oh! Thank you! <33
yw and now @Wondergiirl you are on your own g'night
Night ! :D
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