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Mathematics 14 Online
OpenStudy (clamin):

PLEASE HELP!! MEDAL!!

OpenStudy (clamin):

OpenStudy (anonymous):

So we got \[3n^2 + 5n +7 = 5\] And we need to factor it. So what do you suppose is the first step?

OpenStudy (anonymous):

Or is this where you are stuck?

OpenStudy (anonymous):

First, you need to move everything to one side. Then you need to use something called Pythagorean's Theorem, which gives you a way to solve for the values of x at 0.

OpenStudy (clamin):

yes im stuck

OpenStudy (anonymous):

yes as Luke said you need to move everything to one side so you got it equal to 0 so that is very simple you get. \[3n^2 + 5n +2 = 0\] Now comes the toughed part. FOILing to get what x equals. the factors of 3 are just 3 and 1 and factors of 2 are just 1 and 2 so this makes it pretty simple \[(3n \pm2)(n \pm1)=0 \] Now where i placed the plus and minus sign you need to determine that would make the expression true and as you can both should be plus so your factored expression is \[(3n +2)(n + 1) = 0\] Now set both factors equal to zero and solve for n to get your answer set

OpenStudy (clamin):

the answer is not on the chioces..@hilbertboy96

OpenStudy (anonymous):

You have to find for which values of n, that equation he gave you is 0. You do that by doing one term at a time. (3n+2) then (n+1).

OpenStudy (anonymous):

so yes solve 3n + 2 = 0 and you get one solution, then do n + 1 = 0 and you get another, These two solutions should be one of your choices

OpenStudy (clamin):

i get 3n^2+5n+2=0

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