PLEASE HELP!! MEDAL!!
So we got \[3n^2 + 5n +7 = 5\] And we need to factor it. So what do you suppose is the first step?
Or is this where you are stuck?
First, you need to move everything to one side. Then you need to use something called Pythagorean's Theorem, which gives you a way to solve for the values of x at 0.
yes im stuck
yes as Luke said you need to move everything to one side so you got it equal to 0 so that is very simple you get. \[3n^2 + 5n +2 = 0\] Now comes the toughed part. FOILing to get what x equals. the factors of 3 are just 3 and 1 and factors of 2 are just 1 and 2 so this makes it pretty simple \[(3n \pm2)(n \pm1)=0 \] Now where i placed the plus and minus sign you need to determine that would make the expression true and as you can both should be plus so your factored expression is \[(3n +2)(n + 1) = 0\] Now set both factors equal to zero and solve for n to get your answer set
the answer is not on the chioces..@hilbertboy96
You have to find for which values of n, that equation he gave you is 0. You do that by doing one term at a time. (3n+2) then (n+1).
so yes solve 3n + 2 = 0 and you get one solution, then do n + 1 = 0 and you get another, These two solutions should be one of your choices
i get 3n^2+5n+2=0
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