Question

What is the quadratic function that is created with roots -10 and -6 and a vertex at (-8, -8)?

Answer 1

there is really too much information here
your math teacher has overoaded the question
one root and a vertex would do it

Answer 2

what happened to your hat?

Answer 3

one way is to start with
\[y=a(x+10)(x+6)\] and then solve for \(a\)

Answer 4

since the point \((-8,-8)\) is on the graph you know if \(x=-8\) then \(y=-8\) and you can solve
\[-8=a(-8+6)(-8+10)\] or
\[-8=4a\]

Answer 5

oops that was wrong, should be

\[-8=8a\]

Answer 6

omg thanks so much

Answer 7

what is this, picture day?

Answer 8

it could be

Answer 9

btw you did get
\[y=-(x+10)(x+6)\] or \[y=-x^2-16 x-60\] right?

Answer 10

ya

Answer 11

@satellite73 are you sure?

Answer 12

vertex at (-8, -8)
so f(-8) =should be -8

Answer 13

that makes sense