PRE CALC HELP (picture attached)
@amistre64
you are to use the unit circle do you have that handy?
http://www.mathsisfun.com/geometry/images/circle-unit-304560.gif if not you can find it in that link
pretend we want to solve \[\csc(\theta)=-2\] since the unit circle is in terms of cos and sin you can choose to write csc as 1/sin so we have \[\frac{1}{\sin(\theta)}=-2 \text{ \implies } \sin(\theta)=\frac{-1}{2} \\ \text{ so we want \to find when the y value is -1/2 } \\ \text { and see what the corresponding } \theta \text{ is } \] So we have y=-1/2 at theta=210 deg and 330 deg
but I don't understand what they are asking for
those answers i found are between 0 and 360 degs by the way we could find answers in a different rotation around the circle
okay what about the 3 pi over 2 ?
cos(3pi/2)=0 sin(3pi/2)=-1
we can see this on the unit circle there there at 3pi/2 radians the x tells us cosine there is 0 the y tells us sine there is -1
can you help me with #2?
R / Y for csc
have you done number 1?
they are looking for theta such that theta satifies the following sin(theta)=-1/2 and there is between pi and 3pi/2
I thought it was 210 and 330
well 330 is not between 180 an 270 deg
so just 210
you instructions are weird it says to answer with degs and rads but the inequality is in terms of rads which means your answer should be in terms of radians so I know you must like the radians answer but listing the degree answer for number 1 seems weird to me since they have already picked theta to be in radians
you should list the answer in radians and then write beneath it the following: sin(theta)=-1/2 , 180 deg<theta<270 deg when theta=210 deg
ok thank you:)
can you help me with 2?
ok well like in the example I gave you I wrote the equation in terms of sine try that here
so it would be in the 2nd quadrant
150?
yep and since the question says write in radians I would write the equation again and inequality in terms of radians in the answer in radians
so beneath that I would write: csc(theta)=2, pi/2<theta<pi when theta=150pi/180=15pi/18=5pi/6
okay I think I understand now ! thanks!
np do the 3rd one and write what you think here and i will check you one more time
300?
yep
so then for that question beneath it I would put tan(theta)=-sqrt(3), 3pi/2<theta<2pi when theta)=300pi/180=30pi/18=5pi/3
do you know why I'm doing this extra line stuff?
The instructions are weird.
It says they want it in both degrees and radians.
It also said find the answers within two rotations but that is impossible in the questions we have just solved.
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