8/ (-0.02) easy way to know how to solve
have you covered the exponents rules yet?
need some review please
http://www.math-play.com/image-exponents-rules.jpg <--- any ideas on how to convert the numerator to an exponential form?
yah forgot all those rules
hmmm what are you supposed to do with the equation anyway?
its asking to divide
\(\bf \cfrac{8}{-0.02}\quad \begin{cases} 8\to 2\cdot 2\cdot 2\\ 0.\underline{02}\to\frac{0\underline{02}}{1\underline{00}}\to \frac{2}{100}\to 2\cdot \frac{1}{100}\to 2\cdot 10^{-2} \end{cases}\qquad thus \\ \quad \\ \cfrac{8}{-0.02}\implies \cfrac{\cancel{ 2 }\cdot 2\cdot 2}{-\cancel{ 2 }\cdot 10^{-2}}\)
so its -400? i dont get it
well... notice....all I did was factor the top and bottom the bottom by making it a 10base type so \(\large { \cfrac{8}{-0.02}\quad \begin{cases} 8\to 2\cdot 2\cdot 2\\ 0.\underline{02}\to\frac{0\underline{02}}{1\underline{00}}\to \frac{2}{100}\to 2\cdot \frac{1}{100}\to 2\cdot 10^{-2} \end{cases} \\ \quad \\ \cfrac{8}{-0.02}\implies \cfrac{\cancel{ 2 }\cdot 2\cdot 2}{-\cancel{ 2 }\cdot 10^{-2}}\implies \cfrac{4}{-10^{-2}}\implies \cfrac{4}{-0.01} }\)
right its looking for a whole number but i dont know how to read the question
a whole number? well... you can just do a division of that... that'd give you actually -400
unless you mean to do it by long division
yes! but where do i start with dividing?
say 8/-0.02 so..... you'd notice first how many decimals on either the dividend and divisor and add that many zeros to the other, while dropping the decimal point say in this case dividend 8 has no decimals.... so no zeros added to the divisor divisor -0.02 has 2 decimals so we add 2 zeros to 8 so it ends up looking like \(\large \cfrac{8}{-0.02}\implies 8\div -0.\underline{02}\implies 8\underline{00}\div -\quad 2\)
once we dropped the decimal point from -0.02 we would end up with -002 which is in significant numbers only -2
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