Question

m+1 divide by 6 + m-3 divide by 3

Answer 1

Use the exact same method as in the previous problem.

Answer 2

I did bro

Answer 3

\[m + 1\div 6 + m-3 \div 3\]

Answer 4

\[\frac{ m + 1 }{ 6 } + \frac{ m-3 }{ 3 }\]
first thing to do is to find the LCD

Answer 5

6

Answer 6

then you'll have it as
\[\frac{ (m + 1) + 2(m - 3) }{ 6 }\]

Answer 7

simplify the numerator

Answer 8

how you get 2

Answer 9

\[\frac{ m-3 }{ 3 } \rightarrow \frac{ 2(m - 3) }{ 6 }\]
Since you have 6 as the LCD, to find the value for the numerator, all you have to do is divide the LCD with the original denominator in which in that case: 6 is the LCD and 3 is the original denominator.. so you'll have 2 then multiply it to the numerator
this is also what happened to the first term
\[\frac{ m+1 }{ 6 } \rightarrow \frac{ 1(m+1) }{ 6 }\]
only that 6/6 is 1 so won't notice it that much

Answer 10

so that be the answer

Answer 11

sorry what

Answer 12

notice that when you simplify it to lowest term dividing both the numerator and the denominator by 2 you'll come up with the original expression
\[\frac{ 2(m-3) }{ 6 } \rightarrow \frac{ \frac{ 2 }{ 2 }(m-3) }{ \frac{ 6 }{ 2 } } \rightarrow \frac{ m-3 }{3 }\]

Answer 13

\[\frac{ m+1 }{ 6 } + \frac{ m - 3 }{ 3 } = \frac{ (m+1) + 2(m-3) }{ 6 }\]
simplifying it further you'll have
\[ = \frac{ (m+1) + ((2)m - 2(3)) }{ 6 }\]
\[ = \frac{ (m+1) + (2m - 6 }{ 6 } \]
\[ = \frac{ m+1 + 2m - 6 }{ 6 } \]
\[ = \frac{ 3m - 5 }{ 6 } \]

Answer 14

thanks man