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A ball is thrown vertically upward from the top of a 100 foot tower, with an initial velocity of 10 ft/sec. Its position function is s(t) = –16t2 + 10t + 100. What is its velocity in ft/sec when t = 2 seconds?
it is supposed to say negative 16
that is what the question marks are
is it -38?
Oh wait a sec, you're given poistion function... so differentiating it you would get velocity
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\[\large v(t) = s'(t) = \left( –16t^2 + 10t + 100\right)'\]
i cant see it
refresh ur page
differentiate and plugin t = 2
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oh got it! thanks!
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