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Mathematics 15 Online
OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

A ball is thrown vertically upward from the top of a 100 foot tower, with an initial velocity of 10 ft/sec. Its position function is s(t) = –16t2 + 10t + 100. What is its velocity in ft/sec when t = 2 seconds?

OpenStudy (anonymous):

it is supposed to say negative 16

OpenStudy (anonymous):

that is what the question marks are

OpenStudy (anonymous):

is it -38?

ganeshie8 (ganeshie8):

Oh wait a sec, you're given poistion function... so differentiating it you would get velocity

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

\[\large v(t) = s'(t) = \left( –16t^2 + 10t + 100\right)'\]

OpenStudy (anonymous):

i cant see it

ganeshie8 (ganeshie8):

refresh ur page

ganeshie8 (ganeshie8):

differentiate and plugin t = 2

OpenStudy (anonymous):

oh got it! thanks!

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