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How do I find the integral of (x^2+x+sqrt(x+1))/(x+1) dx
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A substitution hint would be maybe enough.
\[\int\limits_{}^{}\frac{x(x+1)+\sqrt{x+1}}{\sqrt{x+1}} dx \] is that right ?
try the sub u=sqrt(x+1) u^2=x+1 2udu=dx
\[\int\frac{x^2+x+\sqrt{x+1}}{x+1}~dx=\int x~dx+\int(x+1)^{-1/2}~dx\]
Thanks both!
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