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Why is 15t (t-5) the answer to 15t^2-75t?
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becoz on opening bracket we multiply the terms
a(b-a)=ab-a^2
here 15t.t-15t.5
that is 15t^2-75t
@niine Did you understand danish's answer?
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When you multiply exponents you add them \[t \times t = t^2\] it works with normal numbers to, keep in mind everything is to the one, so look. \[2^1 \times 2^1 = 2^{1+1} = 2^2 = 4\] And for your question you have to distribute the 15t over everything in the brackets, as so.|dw:1412495941489:dw|
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