Determine whether the equation is always, sometimes, or never true.
6(x+1)=2(5+3x)
6x+6=10+6x pls help stuck on this

Question

dumbcow · Answer

ok now combine terms

get "x" on one side, constants on other

anonymous · Answer

i end up minusing 6 from both 6x and coming up with 0x

dumbcow · Answer

correct

0x = 4

anonymous · Answer

oh ok then i had it right can you hel with one more
 thanks

dumbcow · Answer

this means 0=4 which is false right

the equation is never true

dumbcow · Answer

sure

anonymous · Answer

0.5(x-3)-(1.5-x)=5x

anonymous · Answer

i know the answer will be 0 idk how to get to it tho

dumbcow · Answer

distribute

---> .5x -1.5 -1.5 +x = 5x

combine terms

--> 1.5x -3 = 5x
--> 3.5x = -3

solve
---> x = -3/3.5

anonymous · Answer

oh its not 0 ok thx

anonymous · Answer

internet different sources told me 0

dumbcow · Answer

yeah unless equation is wrong....is answer supposed to be x=0 ?

anonymous · Answer

yes equation is wrong my bad its 0.5(x-3)+(1.5-x)=5x

dumbcow · Answer

haha big difference :)

ok well can you distribute and combine terms on your own this time....follow my example

anonymous · Answer

ok thanks