Find the distance of line AB if A (3,5) and B (-3,-3). A. 8 B. 6 C. 12 D. 10 When I use the distance formula to find the answer, I get 2 but that isn't even an option here. Help?
which formula you used
3--3 is not 0
5--3 is not 2
@Nnesha the distance formula
@amistre64 I was following an example that added 3+(-3) and 5+(-3). is that not right?
the distance between the xs is subtraction, not addition when we want to find the distance between 2 things, a and b, we do: b - a
d = sqrt( (x1-x2)^2 + (y1- y2)^2 ) ^ ^
lets 'move' the points so that one of them is at the origin A (3,5) and B (-3,-3). -3,-5 -3,-5 ------------------- A' = 0,0 B' = -9,-8 the distance hasnt changes, just where they are located
lol, -6,-8
@amistre64 d = (-3 - 3)^2 + (-3 - 5))^2 = (-6)^2 + (-8)^2 = -14 (?)
sqrt(36 + 64 ) not sqrt(6+8)
how you get negative answer when you take square its mean - 6 times - 6 so its just 36 and same with 8 square
@amistre64 whoops, I forgot to square it lol so d = 10
yep :)
:)
@amistre64 @Nnesha thanks to the both of you :)
nope mostly thanks to @amistre64
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