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OpenStudy (anonymous):
0.5(x-3)+(1.5-x)=5x
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TheSmartOne (thesmartone):
distribute the .5 and 1.5 and move all the variables. show what you did and then from there I can help you...
OpenStudy (anonymous):
.5x-1.5+1.5-x=5x
OpenStudy (anonymous):
there is nothing to distrubute into right side
TheSmartOne (thesmartone):
Ok now move all the terms with x onto one side...
OpenStudy (anonymous):
thats where im stuck on i know the answer will come out to 0 but i have no idea how to get to that point i not sure which direction to add like terms
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TheSmartOne (thesmartone):
Ok
TheSmartOne (thesmartone):
.5x-1.5+1.5-x=5x
So lets simplify.
-1.5+1.5=0
so .5x-x=5x
OpenStudy (anonymous):
oooooooooooooooooooooh i just realized
OpenStudy (anonymous):
ive been getting zero thi whole time but i thought you cant bring down a zero
TheSmartOne (thesmartone):
now lets add x on both sides
.5x-x+x=5x+x
-x+x=0 so
.5x=6x
subtract .5x to both sides
.5x-.5x=6x-.5x
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TheSmartOne (thesmartone):
Then you will get 0=5.5x and obviously x will have to equal to 0..
OpenStudy (anonymous):
ok thanks for the help
TheSmartOne (thesmartone):
because 0/5.5 =x and o over anything equals to 0.
TheSmartOne (thesmartone):
Don't get confused when someother number over 0 is not equal to 0 it is undefined...
TheSmartOne (thesmartone):
For example\[\frac{ 0 }{ 5 }=0\]
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TheSmartOne (thesmartone):
and \[\frac{ 5 }{ 0 }=undefined\]
TheSmartOne (thesmartone):
Do you get it?
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