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How to find the fourth order Taylor polynomial of the function cos(x^2)
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gonna need a few derivatives to play with
let cos(x^2) = f(x) = ax^4 + bx^3 + cx^2 + dx + e [cos(x^2)]' = f'= 4ax^3 + 3bx^2 + 2cx + d [cos(x^2)]'' = f''= 4.3ax^2 + 3.2bx + 2c [cos(x^2)]''' = f'''= 4.3.2ax + 3.2b [cos(x^2)]'''' = f''''= 4.3.2a we can therefore solve for a, then b, then c, then .... all the way to e and our 4th degree polynomial function is defined
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