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Mathematics 20 Online
OpenStudy (anonymous):

help please

OpenStudy (anonymous):

The red graph (1) is the graph of f(x) = 2x. Describe the transformation of the blue function (2) and write the equation of the graph.

OpenStudy (anonymous):

OpenStudy (amistre64):

well, proper notation helps. f(x) is not equal to 2x

OpenStudy (anonymous):

okay

OpenStudy (amistre64):

what are your thoughts about a transformation we could apply?

OpenStudy (anonymous):

it moves up 3 units?

OpenStudy (amistre64):

hmm, it might 2^x + 3 could be a start, we need to flip it over tho and so im thinking we could reflect it first, then move it up

OpenStudy (amistre64):

to flip it over we want to multiply thru by -1 y = 2^x -y = -2^x when x=0, we want -y=1 1 = -2^0 + k 2 = k this gives us a new function so far as say: g = -2^x + 2 which we may need to adjust to hit key points on the graph

OpenStudy (amistre64):

(1,-1) (2,-5) -1 = -a2^(1) + 2 -3 = -2a a = 3/2, which aint gonna fit since that gives us 2,-4 instead of 2,-5 so this approach is not going to be exactly what we require

OpenStudy (anonymous):

okayyy

OpenStudy (amistre64):

it may be a flip, lift and shift

OpenStudy (amistre64):

y = -2^(x-h) + 3 1 = -2^(0-h) + 3 -2 = -2^(-h), when -h=1 so we might be able to work it as y = -2^(x+1) + 3

OpenStudy (anonymous):

so what would i write for the transformation of the blue line?

OpenStudy (amistre64):

thats what ihave been working to detemrine, i think i hve found a suitable transformation

OpenStudy (amistre64):

reflect, left, and shift

OpenStudy (amistre64):

ugh .. typo reflect, lift, shift

OpenStudy (anonymous):

and would y = -2^(x+1) + 3 be the equation?

OpenStudy (amistre64):

i believe so, it hits al the visual points that the blue line does

OpenStudy (anonymous):

okayy thank you!

OpenStudy (amistre64):

yw

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