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Find the equation of the line that passes through (-2,-1) that is parallel to 2x-3y=9.
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if you solve say " 2x-3y=9." for "y" what would it look like?
Oh. I would have to plug in the (-2, -1) right?
well... nope.... not quite.... is simpler if you solve " 2x-3y=9." for "y" firstly
Would I have to subtract the 2x and put it with the 9? 3y=-2x+9 Actually. I'm not sure. :[
yeap
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Then from there do I plug it in? Or, is there another step that I'm missing?
well... you need to isolate the "y" so subtract 2x and then divide by -3
Is this what you meant? y=-2x+9/3
hmmm you may want to brush up your section on linear simplification first I'd think
Okay. I'll go do that. Thanks for the help though. :]
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