What is the equation of the line tangent to the curve at P. Point P (0,1) and the curve that it lies on is √((x^(2)+y^(2))=tan((π/4)(x+y)). How do I begin? I tried implicit differentiation but I had too difficult of a time with it. I need to find the slope for y-1=m(x-0), right?

Question

zepdrix · Answer

Hey veronica :)
Yes you have the right idea!

Implicit differentiation giving you some trouble?
Hmm let's see....

zepdrix · Answer

$$\Large\rm \sqrt{x^2+y^2}=\tan\left[\frac{\pi}{4}(x+y)\right]$$This is the bad boy that we have to deal with?
Did I copy that correctly?

zepdrix · Answer

Do you remember your $\Large\rm \sqrt{x}$ and $\Large\rm \tan x$ derivatives?

zepdrix · Answer

Vron?? D: Where hast thou gone?

anonymous · Answer

Oh sorry. I believe it is (1/2)x^(-1/2 and sec^(2)x, right?