Question

2^x * 4^x / 8^x - 1

Express in simplest form with a prime number base.
Please Explain.

Answer 1

ok... so just checking its

\[\frac{2^x \times 4^x}{8^{x - 1}}\]

Answer 2

Yeah

Answer 3

ok... well you need to know a few things about 4 and 8

\[\frac{2^x \times (2^2)^x}{(2^3)^{x - 1}}\]

now all the terms are in the same base...

so the index laws you need are

1. Power of a power... multiply the powers

\[(x^a)^b = x ^{a \times b}\]

2. multiplying terms with the same base, add the powers

\[x^a \times x^b = x^{a + b}\]

3. dividing the same base, subtract the powers

\[\frac{x^a}{x^b} = x^{a - b}\]

hope it all helps..

Answer 4

Thank you :)