Question

What values of x make the two expression below equal?
(2x+1)(x-7)/11(x-7)=2x+1/11

A.) All real numbers expect -1/2
B.) All real numbers
C.) All real numbers expect -1/2 and 7
D.) All real numbers expect 7

Please HELP! @saifoo.khan @iambatman @mathgeek27 @Joel_the_boss @mathmath333 @ganeshie8 @undeadknight26

Answer 1

What do you think?

Answer 2

Um I really don't know do you plug in something?

Answer 3

No.
Do you know about restrictions?

Answer 4

No I do not.

Answer 5

\[\frac{(2x+1)(x-7)}{11(x-7)}=\frac{2x+1}{11}\]
Okay, so if I plug x =7, it will be:
\[\frac{(2x+1)(x-7)}{11(7-7)}=\frac{2x+1}{11}\]
\[\frac{(2x+1)(x-7)}{0}=\frac{2x+1}{11}\]
No fraction can be divided by 0 as it makes the fraction infinite.

So x should NOT be equal to 7.
This is called restriction.

Answer 6

Okay so I would pick D?

Answer 7

Okay, I don't understand what you just did.

Answer 8

Wait. it will be D.
Ignore what I did last.

Answer 9

Okay, thank you so much for your help!