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Find the Area enclosed by the curve "y=sqrt(5x+4)", x-axis, y-axis, and the line x=1
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the area is integration, a picture is nice but immaterial at the moment
|dw:1412617723571:dw|
|dw:1412617653487:dw| \[A=\int_{a}^{b}f(x)~dx\]
I got as far as \[\int\limits_{0}^{1} \left( \sqrt{5x+4} \right)dx\]
convert the rt to a power
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and, if you cant see it clearly, try a u substitution
\[\int\limits_{0}^{1}\left( 5x+4 \right)^{\frac{ 1 }{ 2}}dx\]
if we let 5x+4 = u what does dx become?
i really have no idea
take a derivative with respect to x ... ive got real life issues pressing so ill be away for a few hours at best
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