Limits question
\[\lim_{t \rightarrow 5}\frac{ 4t^2-100 }{ t-5 }\] = 40?
so I assumed you tried factoring the top and got (2t-10)(2t+10)=2(t-5)(2t+10)?
actually no but i should have
what did you do ?
the cheapo way, plugged numbers in coming from both positive and negative sides like 5.01 and 4.99
lol
try the factoring way much faster and it will confirm your answer you got numerically
one more question
when im finding vertical asymptotes...ah nevermind ill figure it out.
\[f(x)=\frac{ x^2-9x+14 }{ x^2-5x+6 } = \frac{ x-7 }{ x-3 }\] find vertical asymptotes.\[x \rightarrow 3^- = +oo\] .\[x \rightarrow 3^+ = -oo\] but why wouldnt i consider x->7? seems to me that as the numerator gets smaller and smaller f(x) becomes infinitely small? .\[x \rightarrow 7^- = +oo\] .\[x \rightarrow 7^+ = -oo\]
i c
as x approaches 7 the top approaches 0 so we have 0/not 0 =0
like so we don't have the limit is positive or negative infinity there
the other you wrote about x=3 looks good
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