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Physics 17 Online
OpenStudy (anonymous):

A vertebra is subjected to shearing force of 465 N. Find the shear deformation, taking the vertebra to be a cylinder 3.00cm high and 3.00cm in diameter. The shear modulus for vertebrae is 8.00 *10^10 N/m^2

OpenStudy (anonymous):

Shear stress is defined as the Force acting on an Area. You are given F = 465 N For a cylinder, surface area is given by: 2*pi*r*h + 2*pi*r^2 radius r in this case is 3/2 cm height h in this case is 3 cm Try finding the shear stress now: S = F/A

OpenStudy (anonymous):

2.47*10^-7 m came out to be the correct answer. it needed converted to m, i left that part out of the question.

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