Let f(x) be odd and integral between -4 to 8 f(x)dx=1. Integral Between 4 to 8 f(x)dx=?
second time i have seen this problem and i couldn't get it the first time seems like it could be anything
I know that there's a specific way to do it, but problem is i don't know how to apply it. xD
ooh doh
\[\int_{-4}^4f(x)dx=0\] because the function is odd!!
Apparently It's not the right answer. This is what I got a hint for.
jeez sometimes i think my brain went on vacation
yea so the part from -4 to 4 contributed nothing
the part from 4 to 8 is one
Sometimes I want to cry in a corner.
lol me too
\[\int_{-4}^8=\int_{-4}^4+\int_4^8=0+\int_4^8=1\]
That seems right. lol actually yeah!
oh yeah, it is right
i would bet \(\$87\) on it
Hahaha Thanks :)
And if f is odd then F is even so F(4)=F(-4) \[\int\limits_{-4}^{8}f(x) dx=F(8)-F(-4)=F(8)-F(4)=1\]
\[\text{ so } \int\limits_{4}^{8}f(x) dx=1 \]
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