How do i factorise x^3+4x^2+x-6, so i can see the X-intercepts in the form of the three bracket
(x )(x )(x )

Question

How do i factorise x^3+4x^2+x-6, so i can see the X-intercepts in the form of the three bracket
(x  )(x  )(x  )

anonymous · Answer

really you have to find the zeros before you can factor

anonymous · Answer

fortunately for you they are easy to find
$1$ is a zero by inspection, since $1+4+1-6=0$ so you can factor as 
$$(x-1)(\text{ some quadratic})$$

anonymous · Answer

and from that point how to i get it into three brackets? because the x-1 and the "some quadratic" still will not give me the 3 points on the X-axis

campbell_st · Answer

do some synthetic or polynomial division to get the quadratic...

campbell_st · Answer

|dw:1412659373768:dw|

so you have 

$$(x -1)(x^2 + 5x + 6)$$

now just factor the quadtratic