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integrate -9 to 0 (2+sqrt of 81-x^2)dx, without using an antiderivative
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\[\int\limits_{-9}^{0}(2+\sqrt{81}-x^2) dx ? \]
\[\int\limits_{-9}^{0}(2+\sqrt{81-x^2})dx\] if it is this one we can do a circle thingy :)
I suspect it is the latter.
well for the first little part rectangle second part circle \[\int\limits_{-9}^{0}2dx+\int\limits_{-9}^{0}\sqrt{81-x^2} dx\]
@xjasmineg are you there?
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yeah, i'm here!
and its the second one!
it says evaluate the exact value using area?!
@myininaya ?
The first definite integral is the area of a rectangle with height 2 units and length 9 units. The second one is the area of a quarter of a circle of radius 9.
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