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Divide. Assume that all expressions are defined. x+3/x^2-2x+1 divided by x+3/x-1 1/x-1 x-1 x^2+6x+9/x-1 1/x^2+1
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\[x+3/x^2-2x+1 .x-1/x+3\]
if u recirocal x+3/x-1 the sign will change into multiply between the eq.
x+3 will get cancelled u will be left with x^2-2x+1/x-1
u understood this much
yes
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\[\frac{x+3}{x^2-2x+1} = \frac{x+3}{(x-1)(x-1)}\]
\[\frac{x+3}{(x-1)(x-1)} \times \frac{x-1}{x+3} = \frac{1}{x-1}\]
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