Question

What is the equation of the line (in slope-intercept form) that passes through the given point and is perpendicular to the graph of the given equation?

(6,negative -2); y = negative-3x + 4











y = negative-1 over 3x − 4










y = 1 over 3x + 4










y = negative-3x − 4










y = 1/3x − 4

Answer 1

@gorv
@Joel_the_boss

Answer 2

@iGreen

Answer 3

y = -3x + 4

can you tell me the slope of this line ?

Answer 4

-3x

Answer 5

In y = mx + b form, the slope is in the m position. So what is the slope of the given equation

Answer 6

-3

Answer 7

@iGreen

Answer 8

correct....-3 is the slope. However, we are looking for a perpendicular line and that contains a negative reciprocal slope. So we need the negative reciprocal of -3. To find the negative reciprocal, just " flip " the slope and change the sign. So our new slope is 1/3....see how I flipped the slope and changed the sign.

Now we use y = mx + b form
slope(m) = 1/3
(6,-2)...x = 6 and y = -2
we already know the slope(m) so we have to find the y intercept(b)
now we sub
-2 = 1/3(6) + b
-2 = 2 + b
-2 - 2 = b
-4 = b

so your perpendicular line is : y = 1/3x - 4

any questions ?

Answer 9

Thanks, now I understand :)

Answer 10

glad to help :)