10 + h/3 = 1 ? Solve for h and show steps please
subtract 10 on both sides, multiply 3 on both sides
so, 1-10=9 9*3=27
27 is ur answer
First you have to subtract 10 from both sides \(\sf \large \color{magenta}{10~-~10~+~h/3~=~1~-~10}\)
So what is \(\sf \large \color{magenta}{10~-~10}\) and \(\sf \large \color{magenta}{1~-~10}\)?
\(\sf \large \color{magenta}{10~-~10~=~0}\) and \(\sf \large \color{magenta}{1~-~10~=~-9}\) So now our problem looks like this \(\sf \large \color{magenta}{h/3~=~-9}\)
So now we take 3 and mltiply it on both sides \(\sf \large \color{magenta}{h/3~x~3~=~-9~x~3}\) Since \(\sf \large \color{magenta}{h/3~x~3}\) gets canceled out it is just h \(\sf \large \color{magenta}{h~=~-9~x~3}\) \(\sf \large \color{magenta}{h~=~-27}\)
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