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Find the linearization l(x) of the function at a. F(x)=sinx a=pi/6
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if we have a slope and a point, could we make a line equation with them?
It doesn't give me a point or slope just that
oh it s gives it to you ...
the point is a,f(a) and the slope is defined as f'(a)
y - f(a) = m(x-a) y - f(a) = f'(a) (x-a)
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So would I take the derivative of sin then plug in pi/6 which is1/2
yes
So my answer would just be f'(x)=cos x=cos1/2
y = mx - ma + f(a) a = pi/6 f(a) = sin(pi/6) m=f'(a) = cos(pi/6) y = cos(pi/6)x -pi/6 cos(pi/6) + sin(pi/6) simplify as wanted
Oh ok I see it now I'm overthinking this thank you
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good luck :)
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