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Let f and g be differentiable functions such that f(x)g(x) = x. Show that f(0) != 0 or g(0) != 0.
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okay
f'(x)*g(x)+g'(x)*f(X)=1 if x =0 f'(x)*0+g'(x)*0=1 how is this possible?
unless there is some division by zeros and infinity stuff going on
in which case we cannot say the lim as u approach that point exists so the derivative is not defined
pretty cool
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what about he produc t of 3 functions and n fuctions will they also be undefined if they all had evaluated to 0 at x=0
think about that it has the same idea
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