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Mathematics 17 Online
OpenStudy (anonymous):

Let f and g be differentiable functions such that f(x)g(x) = x. Show that f(0) != 0 or g(0) != 0.

OpenStudy (swissgirl):

okay

OpenStudy (swissgirl):

f'(x)*g(x)+g'(x)*f(X)=1 if x =0 f'(x)*0+g'(x)*0=1 how is this possible?

OpenStudy (swissgirl):

unless there is some division by zeros and infinity stuff going on

OpenStudy (swissgirl):

in which case we cannot say the lim as u approach that point exists so the derivative is not defined

OpenStudy (swissgirl):

pretty cool

OpenStudy (swissgirl):

what about he produc t of 3 functions and n fuctions will they also be undefined if they all had evaluated to 0 at x=0

OpenStudy (swissgirl):

think about that it has the same idea

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