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zeroes of y=-2x^3-2x^2+12x
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\(y=-2x^3-2x^2+12x\) To find the zeroes of this, input 0 for 'y'. \(0=-2x^3-2x^2+12x\) Factor: \(0 = 2x(-x + 2)(x + 3)\) Therefore, x = -3, 2, and 0.
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