Question

prove (sec^2x -1)/(sec^2x) = sin^2x

Answer 1

sec(x)=1/cos(x)
(1/cos^2(x)-1)/(1/cos^2(x))=(1/cos^2(x)-1)*cos^2(x)=1-cos^2(x)=sin^(x)

Answer 2

\[
\frac{\sec^2(x) - 1}{\sec^2(x)} = \frac{\sec^2(x)}{\sec^2(x)} - \frac{1}{\sec^2(x)} =
1 - \cos^2(x) = \sin^2(x)
\]

Answer 3

thanks guys

Answer 4

You are welcome.