Question

What is the best way to classify each equation?
1. 8x+24=2(4x+12)
2. 5x+18-x=2(2x+8)
3. 7(3x-2)=20x-13
4. 3x+2(x-10)=5(x-4)
Give each one of the numbers a letter:
A. Identify
B. Contradiction
C. Neither

Answer 1

\[ 8x+24=2(4x+12)\]if both sides are equal, it is an identity
lets check by the distributive law
\[ 8x+24=2(4x+12)\\
8x+24=8x+24\] yup they are equal

Answer 2

Identity

Answer 3

\[5x+18-x=2(2x+8)\] multiply out and get
\[5x+18-x=4x+16\] combine like terms andget
\[4x+18=4x+16\]

Answer 4

seems unlikely that you could add 18 to a number, add 16 to that same number, and get the same answer
that makes this a "contradiction"

Answer 5

if f(x) = g(x) is true for all x, then we have an identity

if f(x) = g(x) is false for all x, then we have a contradiction

if f(x) = g(x) is true for only a few specific x, then we neither an id nor a contra

Answer 6

@amistre64 By the way that dosent help because i dont know how to solve for X in the first place

Answer 7

@iambatman help?