Question

Calculate the area of the shaded region

Answer 1

2ii)

Answer 2

@ikram002p

Answer 3

can you find areas of APO, BQO and BOA?

Answer 4

BOA=1/2*12*5=30

Answer 5

BQO=1/2*5^2*1.1759=14.698

Answer 6

so APO=15.30125

Answer 7

great. now AOB = AQO + QPO + POB
AOB = AQO + QPO + POB + QPO - QPO

Answer 8

so AQO + QPO = AOP
POB + QPO = BQO
therefor
AOB = AOP + BQO - QPO

Answer 9

@lochana for the small triangle shouldnt it be isoceles OP=5 OB=5 and so their angles are the same

Answer 10

AOB=AQO+OBQ AQO=(30-(0.5*25*1.1759)=15.30125

Answer 11

oh your answers above are wrong. ok. you should use (theta)r^2 to find BQO and APO areas

Answer 12

30=15.30125+OPQ+BOP 14.69875=OPQ+BOP

Answer 13

the area of sector is equal to 14.69875 and the area of triangle =30 so the area of AQO=15.30125

Answer 14

do you have any clue what we are going to do next

Answer 15

so APO =(1/2) 12^2*0.3948=28.4256

QPO = 28.4256 - 15.3013 = 13.1243

Answer 16

what equation have you used to calculate the area of APO

Answer 17

oh so APO and QOB are sectors

Answer 18

1/2(theta)r^2.

Answer 19

Thanks @lochana