Question

Consider the function below. (Use exact numbers in your answers.) f(x)=(5x)/1+ x^2 a) Find F '(2). (b) Use the answer from part (a) to find an equation of the tangent line to the curve y = F(x) at the point (2, 2).

Answer 1

really need to edit this, try the equation editor

Answer 2

f(x)=\[(5x) \div 1+ x ^{2}\]

Answer 3

is that better? @satellite73

Answer 4

no not really, but i suppose it means
\[f(x)=\frac{5x}{1+x^2}\]

Answer 5

and you want \(f'(x)\) right?

Answer 6

for this you have no choice but the quotient rule
\[\left(\frac{f}{g}\right)'=\frac{gf'-fg'}{g^2}\] with
\[f(x) = 5x, f'(x)=5,g(x)=1+x^2, g'(x)=2x\]

Answer 7

f' (2)

Answer 8

you are going to need \(f'(x)\) to find \(f'(2)\) right?

Answer 9

f'(x)=\[5\div 2x\]

Answer 10

you cannot take the derivative of the numerator and denominator separately and then put one over the other
you have to use the quotient rule for this

Answer 11

whats the quotient rule?

Answer 12

look 6 posts up

Answer 13

\[5(x ^{2}-1)\div (x ^{2}+1)^{2}\]

Answer 14

@satellite73