Question

Ok i need some help with this problem 1/1+x^n + 1/1+x^-n Simplify your answer I can't seem to get the correct answer

Answer 1

\[\huge\frac{1}{1+x^n}+\frac{1}{1+x^{-n}}\]??

Answer 2

Is the problem:
\[
\frac{1}{1+x^n} + \frac{1}{1 + x^{-n}}~~ ?
\]

Answer 3

yes

Answer 4

Multiply the top and bottom of the second one by x^n and then add the two.

Answer 5

ok

Answer 6

\[\large
\frac{1}{1+x^n} + \frac{1}{1 + x^{-n}} =
\frac{1}{1+x^n} + \frac{1}{1 + x^{-n}} * \frac{x^n}{x^n} = \\ \large
\frac{1}{1+x^n} + \frac{x^n}{x^n + 1} = \frac{1+x^n}{1+x^n} = 1
\]

Answer 7

a miracle will occur

Answer 8

ok that makes so much more sense now thank you

Answer 9

You are welcome.

Answer 10

can you help with another problem as well or are you busy?

Answer 11

go ahead.

Answer 12

ok let me copy it real quick

Answer 13

can you open that

Answer 14

No link to click on; nothing to open.

Answer 15

ok let me add another one

Answer 16

try that

Answer 17

Factor 5x out of the numerator. Try to factor the quadratic that you get.
Try to factor the quadratic in the denominator.
Tell me what you get.

Answer 18

ok ill try that

Answer 19

ok so I'm left with 5x(x^2-x-2) on the top and the bottom I'm getting x+2 4x+2 which would give me back the equation but with a positive 13 and thats not right

Answer 20

The (x^2-x-2) in the numerator can be factored further.
The denominator has not been factored properly.

Answer 21

ok yes i see that it can go further ill try it again

Answer 22

the numerator would be 5x(x+1)5x(x-2) and the denominator would be the same thing i got but with negative signs i see what i did wrong

Answer 23

numerator is correct.

Answer 24

the denominator would be 4x-5 times x-2

Answer 25

correct. And the (x-2) will cancel with the same in the numerator.

Answer 26

yes i see that

Answer 27

so I'm left with 5x(x+1) on the top and 4x-5 on the bottom correct?

Answer 28

Yes. \[
\large \frac{5x(x+1)}{(4x-5)}
\]

Answer 29

ok thank you for your help

Answer 30

you are welcome.