Question

The graph of f passes through (-9, 6) and is perpendicular to the line that has a x-int of 7 and y-int of -14
Find slope intercept

Answer 1

does this just mean (-9, 6) (7, -14)

Answer 2

Nope that point and the intercepts are two complete different lines

You need to use the intercepts to develop a line equation and then using the slope of it figure out the slope of the equation you need and develop that one. I will help you one step at a time

Answer 3

So the intercepts are giving you a set of two points

(7,0) and (0,-14) we need to find a slope from these two points so

\[\frac{ y2-y1 }{ x2-x1 } = \frac{ 0-(-14) }{ 0-7 }\]

This equals -2 right?

Answer 4

woops would be positive 2 since 14/7 to keep things consistent

Answer 5

\[\frac{ 0-(-14) }{ 7-0 }\]

Answer 6

With me so far?

Answer 7

yes

Answer 8

Ok so this is our m so far for thisl ine we know that

y=2x + b

Well we don't need the b of this line since we know the slope

A slope perpendicular to this line would be the opposite reciprocal so -1/2

so we have y= -1/2x + b

and now we use (-9,6) to solve for b

6 = -1/2(9) + b
6= -9/2 + b
12/2 = -9/2 + b
17/2 = bSo our line perpendicular to the one formed with the intercepts is

y = -1/2x + 17/2

Answer 9

its all the knowing when to flip stuff that always confuses me. thank you again

Answer 10

although webwork says the answer is wrong

Answer 11

hmmm try

y = 1/2x + 3/2

Answer 12

yep :) right

Answer 13

-1/2 though

Answer 14

Ohhhh haha i copied the point wrong as 9 not -9

Answer 15

6 = -1/2(-9) + b
6 = 9/2 + b
12/2 = 9/2 + b
b = 3/2

Answer 16

thank you!!

Answer 17

Yep! Starting to get it more?