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Mathematics 27 Online
OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (gorv):

do u have Q ?? dear

OpenStudy (anonymous):

no sir, but thanks anyway! :) I already got it done @gorv

OpenStudy (gorv):

welcme btw :)

OpenStudy (gorv):

lol i m not sir

OpenStudy (anonymous):

lol CRAP! sorryyy! :P hahahah @gorv

OpenStudy (anonymous):

i need your help if thats okay @gorv

OpenStudy (gorv):

yeah tell me ..i will do my best

OpenStudy (gorv):

@iamabarbiegirl

OpenStudy (anonymous):

Okay! this is the question

OpenStudy (anonymous):

Identify the degree of the polynomial x2y + 5xy3 - 7y2 + 2. 3 4 5

OpenStudy (gorv):

x and y are variable here

OpenStudy (gorv):

first term x2y degree=2+1=3

OpenStudy (gorv):

second=xy3 degree=1+3=4

OpenStudy (gorv):

so the maxium degree is 4 so it is of degree 4

OpenStudy (gorv):

u got how we find degree??

OpenStudy (anonymous):

oh wooow! you explained it soo well it actually makes sense now lol

OpenStudy (gorv):

just add the power of variable...n max sum of power will be our degree

OpenStudy (anonymous):

yes! i understand now thanks!! i still have more do you mind? you don't have to though :P

OpenStudy (gorv):

ok fire up :P

OpenStudy (anonymous):

:P YEYUHH! xD

OpenStudy (anonymous):

Simplify 13 over the quantity of negative 3 plus 2i. −3 + 2i −3 − 2i −2i − 3 −2i + 3

OpenStudy (gorv):

can u post again ...u can see what happened

OpenStudy (anonymous):

You can't see the one I just posted?

OpenStudy (anonymous):

@gorv

OpenStudy (gorv):

that have lots of question mark

OpenStudy (anonymous):

oh ok i will again! :)

OpenStudy (anonymous):

Simplify 13 over the quantity of negative 3 plus 2i. −3 + 2i −3 − 2i −2i − 3 −2i + 3

OpenStudy (anonymous):

what about now? @gorv

OpenStudy (gorv):

\[\frac{ 13 }{ -3+2i } \] this ???

OpenStudy (anonymous):

yep! :)

OpenStudy (gorv):

\[\frac{ 13 }{ -3+2i }*\frac{ -3-2i }{ -3-2i }\]

OpenStudy (anonymous):

the answer is -3-2i?

OpenStudy (gorv):

yepppp you beat it

OpenStudy (anonymous):

hahahah you beat it! you rock!! GENIUS!

OpenStudy (gorv):

loll u also m just a helper

OpenStudy (anonymous):

I will have the proper equation written next to every choice to make it easier for you! Which of the following represents 6 x to the 3 fourths power in radical form? cubed root of 6 x to the fourth power <---- fourth root of 6 x cubed 6 cubed root of x to the fourth power 6 fourth root of x cubed

OpenStudy (anonymous):

wow it won't let me :P lol

OpenStudy (anonymous):

\[\sqrt[3]{6x ^{4}}\] That's the A choice

OpenStudy (anonymous):

Choice B \[\sqrt[4]{6x ^{3}}\]

OpenStudy (anonymous):

Choice C \[6\sqrt[3]{x ^{4}}\]

OpenStudy (anonymous):

Choice D \[6\sqrt[4]{x ^{3}}\]

OpenStudy (gorv):

\[\sqrt[\frac{ 3 }{ 4 }]{6x}\]

OpenStudy (anonymous):

Hope that helped :P

OpenStudy (anonymous):

don't have that choice @gorv

OpenStudy (anonymous):

which choice should I choose?

OpenStudy (anonymous):

is it \[\sqrt[4]{6x ^{3}}\] ?

OpenStudy (anonymous):

@gorv

OpenStudy (gorv):

first one

OpenStudy (anonymous):

can you please explain it to me? so I can know how to do this next time?

OpenStudy (gorv):

okk

OpenStudy (anonymous):

Thankss!

OpenStudy (anonymous):

I checked another one and this guy says it's the second choice. http://openstudy.com/study#/updates/53c4cc72e4b05c273e9d6608

OpenStudy (anonymous):

@gorv

OpenStudy (gorv):

yeah

OpenStudy (gorv):

\[\sqrt[\frac{ 3 }{ 4 }]{6x}=(6x)^{\frac{ 3 }{ 4 }}\]

OpenStudy (gorv):

thatzz what i told na

OpenStudy (anonymous):

but I don't have that in any of my choices @gorv

OpenStudy (gorv):

ohh sorry ...choice is there forth root of 6x cubed

OpenStudy (gorv):

second one sorry....

OpenStudy (anonymous):

oh don't be! It's a little simple mistake lol

OpenStudy (anonymous):

What is the 3rd term when 5 + 3x2 - 5x4 + 2x3 is arranged in descending order? 5 3x2 -5x4 2x3 @gorv

OpenStudy (gorv):

wait for 2 minute plzzz

OpenStudy (anonymous):

okay np take ur time :)

OpenStudy (gorv):

loll i was helping someone else

OpenStudy (anonymous):

np :)

OpenStudy (gorv):

which term has higest power of x??

OpenStudy (anonymous):

5x?

OpenStudy (gorv):

yeah that will first

OpenStudy (gorv):

now after that

OpenStudy (anonymous):

2x

OpenStudy (anonymous):

and then 3x

OpenStudy (gorv):

5 + 3x2 - 5x4 + 2x3 descending -5x^4 +2x^3+3x^2+5

OpenStudy (gorv):

now u tell me the ans

OpenStudy (gorv):

lollll 3x^2

OpenStudy (anonymous):

i was trying to SOLVE!! lol

OpenStudy (gorv):

itzz okay//....

OpenStudy (anonymous):

thanks.

OpenStudy (gorv):

welcome :)

OpenStudy (anonymous):

Multiply x to the 2 fifths power times x to the 2 ninths power. x to the 2 sevenths power x to the 28 over 45 power x to the 8 over 45 power x to the 4 over 45 @gorv

OpenStudy (gorv):

\[x^{\frac{ 2 }{ 5 }}*x^{\frac{ 2 }{ 9 }}=x^{\frac{ 2 }{ 5 }+\frac{ 2 }{ 9 }}=x^\frac{ 28 }{ 45}\]

OpenStudy (anonymous):

ur a LIFE SAVER!! GOSHH!

OpenStudy (gorv):

lolllllllllll

OpenStudy (anonymous):

Which of the following represents the area of a rectangle whose length is x + 1 and whose width is x + 11? x2+ 11 x2+ 12x + 11 x2+ 11x + 12 x2+ 10x + 11

OpenStudy (anonymous):

@gorv

OpenStudy (gorv):

area= product of length and breadth

OpenStudy (gorv):

area=(x+1)(x+11) =x^2+(1+11)x+11

OpenStudy (gorv):

=x^2+12x+11

OpenStudy (anonymous):

got it!

OpenStudy (gorv):

yooooo

OpenStudy (anonymous):

Frank and Gertrude mow lawns for extra money over the summer. Frank's income is determined by f(x) = 5x + 15, where x is the number of hours. Gertrude's income is g(x) = 4x + 20. If Frank and Gertrude were to combine their efforts, their income would be h(x) = f(x) + g(x) and would be split evenly between the two of them. Assume Frank works 4 hours. Create the function h(x), and indicate if Frank will make more money working alone or by teaming with Gertrude. h(x) = x + 5, work alone h(x) = x + 5, team with Gertrude h(x) = 9x + 35, work alone h(x) = 9x + 35, team with Gertrude

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