Question

if cos (pie x)=x^2-x-5/4 then the value of x is

Answer 1

@ikram002p

Answer 2

cos pie x=(4x^2-4x-5)/4

Answer 3

2<=(2x^2-1)<=10

Answer 4

@waterineyes

Answer 5

Firstly, I am really \(\color{green}{\textsf{Sorry}}\).. I was busy at some another post.. :(

Answer 6

\[\cos (\pi x)=x^2-x-\frac{5}{4}\]

Answer 7

Is this the question??

Answer 8

@rosy2 are you there?? Are you alive?? :P

Answer 9

cos will give values between -1 and 1

Answer 10

-1<=(4x^2-4x-5)/4<=1
multiply both side by 4

Answer 11

-4<(4x^2-4x-5)<4

Answer 12

let forget equal to sign we will add it at the end

Answer 13

now we have 2 equation
-4<4x^2-4x-5
and
4x^2-4x-5<4

Answer 14

yes @waterineyes ,@gorv i was working on some other problem.

Answer 15

u got upto here??

Answer 16

yes

Answer 17

@rosy2

Answer 18

ok can u solve the inequality ??

Answer 19

-4<4x^2-4x-5
add 4 on both side

Answer 20

4x^2-4x-5+4>0

Answer 21

4x^2-4x-1>0

Answer 22

4x^2-4x-5<4
subtract 4 from both side

Answer 23

4x^2-4x-9>0

Answer 24

we have to solve these 2 equation

Answer 25

ok i will work and say the solution

Answer 26

okk..u try n if get a prob we will help u thn

Answer 27

1/2,(1+or-16sqrt(2))/2

Answer 28

we have to find where they are greater than zero or less than zero

Answer 29

i dont have calc with me right now

Answer 30

is it correct?

Answer 31

can i tell u the ans in the eve ??

Answer 32

okay

Answer 33

4x^2-4x-1>0
\[\frac{ 4\pm \sqrt{(-4)^2-4*4*(-1)} }{ 2*4 }\]

Answer 34

\[\frac{ 4 \pm \sqrt{16+16}}{ 8}\]

Answer 35

\[\frac{ 4 \pm \sqrt{16*2}}{ 8 }=\frac{ 4\pm4\sqrt{2} }{ 8 }\]

Answer 36

\[\frac{ 1 \pm \sqrt{2}}{ 2}\]

Answer 37

yes

Answer 38

\[(4\pm \sqrt{160})/8\]

Answer 39

\[(1\pm4\sqrt{10})/2\]

Answer 40

very veryy good rosy

Answer 41

\[(1\pm4\sqrt{10})/2\]

Answer 42

u did a little mistake

Answer 43

4 will not come before sqrt

Answer 44

\[\frac{ 4 }{ 8} \pm \frac{ 4\sqrt{10} }{ 8 }=\frac{ 1 \pm \sqrt{10}}{ 2 }\]

Answer 45

got me??

Answer 46

-9*16=144 add it to 16 we get160 right?