Question

http://prntscr.com/4utb1j

help plz

Answer 1

Oh, what a username..!! Just became a fan of you.. :)

Answer 2

Let me remember the Cosine's Law..

Answer 3

\[a^2 = b^2 + c^2 - 2bc \cdot \cos(A)\]

Answer 4

To find cos(A), you will use:

\[\cos(A) = \frac{b^2 + c^2 - a^2}{2bc}\]

a = 17, b = 22, and c = 30..

Can you find now cos(A), just plug in the values..

Answer 5

@virgin you have keyboard with you no??

Answer 6

See, On Openstudy, we can write here too.. You can try, I guarantee your words will get typed here.. :P

Answer 7

sorry

Answer 8

For what??

Answer 9

i got Undefined

Answer 10

Really??

Answer 11

\[\cos(A) = \frac{30^2 + 22^2 - 17^2}{2 \times 30 \times 22}\]

Answer 12

i still don't get the answer for some reason

Answer 13

Oh sorry, you waited for so long..

Answer 14

What did you get by solving that?

Answer 15

I got:

\[\cos(A) = .829 \implies \cos(A) = 0.83\]

Answer 16

As final answer is in degrees so set your calculator to degrees.. :)

Answer 17

My calculator is giving me : \(A = 33.9^{\circ}\)

Answer 18

oh