Question

The sides of an isosceles triangle are
27
,
27
, and
24yd
long. What is the area of the triangle?
Do not round any intermediate computations, and round your answer to the nearest tenth.

Answer 1

how does this one go?

Answer 2

324

Answer 3

nvrmnd

Answer 4

Haichi its wrong!

Answer 5

yea idk lol sorry

Answer 6

well you can find the perpendicular... which bisects the base



find the value of h, uby using pythagoras' theorem.

then you can find the area

Answer 7

Thank you campbell_st but I still dont get it by the whole bisects thingy!

Answer 8

yea thats confusing lol

Answer 9

Ikr

Answer 10

Do the pic I think I can help

Answer 11

well in an isosceles triangle... the perpendicular from the base... bisects the angle at the top and the base as well... so you end up with a right triangle



and you need the perpendicular height to find the area.

Answer 12

So how do I find the perpendicular height?

Answer 13

just kidding nevermind haha

Answer 14

use pythagoras' theorem

\[27^2 = 12^2 + h^2\]

which becomes

\[h^2 = 27^2 - 12^2\]

Answer 15

Thank you so much! I seriously love you !

Answer 16

think about this.... you can fold an isosceles triangle exactly in half... and you get 2 identical triangles...

the fold line is the perpendicular height... and both triangles are right angled.

Answer 17

I am so sorry but Im really confused now!

Answer 18

fr

Answer 19

using pythagoras you get \[h^2 = 585\] or \[h = 21.2~ yds\]
then the area is \[A = \frac{1}{2} \times 24 \times 21.2 \] hope it helps

Answer 20

Yes exactly I needed a pic what pic did you use?